Y^2+4y=2y+35

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Solution for Y^2+4y=2y+35 equation: 


Simplifying
Y2 + 4y = 2y + 35

Reorder the terms:
Y2 + 4y = 35 + 2y

Solving
Y2 + 4y = 35 + 2y

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
Y2 + 4y + -4y = 35 + 2y + -4y

Combine like terms: 4y + -4y = 0
Y2 + 0 = 35 + 2y + -4y
Y2 = 35 + 2y + -4y

Combine like terms: 2y + -4y = -2y
Y2 = 35 + -2y

Simplifying
Y2 = 35 + -2y

Reorder the terms:
-35 + Y2 + 2y = 35 + -2y + -35 + 2y

Reorder the terms:
-35 + Y2 + 2y = 35 + -35 + -2y + 2y

Combine like terms: 35 + -35 = 0
-35 + Y2 + 2y = 0 + -2y + 2y
-35 + Y2 + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
-35 + Y2 + 2y = 0

The solution to this equation could not be determined.

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